python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)
python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)
how to get a random element from an array in python
import random
names=['Mark', 'Sam', 'Henry']
#Set any array
random_array_item=random.choice(names)
#Declare a variable as a random choice
print(random_array_item)
#Print the random choice
#Or, if you want to arrange them in any order:
for j in range(names):
print(random.choice(names))
print random string from list python
import random
list = ["Item 1", "Item 2", "Item 3"] # List
item = random.choice(list) # Chooses from list
print(item) # Prints choice
# From stackoverflow
# Tried and tested method
select random value from list python
import random
# with replacement = same item CAN be chosen more than once.
# without replacement = same item CANNOT be chosen more then once.
# Randomly select 2 elements from list without replacement and return a list
random.sample(list_name, 2)
# Randomly select 3 elements from list with replacement and return a list
random.choices(set_name, k=3)
# Returns 1 random element from list
random.choice(list_name)
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