python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)how to get a random element from an array in python
import random
names=['Mark', 'Sam', 'Henry']
#Set any array
random_array_item=random.choice(names)
#Declare a variable as a random choice
print(random_array_item)
#Print the random choice
#Or, if you want to arrange them in any order:
for j in range(names):
print(random.choice(names))print random string from list python
import random
list = ["Item 1", "Item 2", "Item 3"] # List
item = random.choice(list) # Chooses from list
print(item) # Prints choice
# From stackoverflow
# Tried and tested methodpython random string
import secrets
secrets.token_hex(nbytes=16)
# this will produce something like
# aa82d48e5bff564f3221d02194611c13how to randomly choose from a list python
random.choice(name of list)python generate random string with lenght
import random
import string
def randStr(chars = string.ascii_uppercase + string.digits, N=10):
return ''.join(random.choice(chars) for _ in range(N))
# default length(=10) random string
print(randStr())
# random string of length 7
print(randStr(N=7))
# random string with characters picked from ascii_lowercase
print(randStr(chars=string.ascii_lowercase))
# random string with characters picked from 'abcdef123456'
print(randStr(chars='abcdef123456'))Copyright © 2021 Codeinu
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