Answers for "np.random choice in list"

33

python choose random element from list

import random

#1.A single element
random.choice(list)

#2.Multiple elements with replacement
random.choices(list, k = 4)

#3.Multiple elements without replacement
random.sample(list, 4)
Posted by: Guest on May-25-2020
0

random choice sampling numpy

>>> np.random.choice(5, 3, replace=False)
array([3,1,0])
>>> #This is equivalent to np.random.permutation(np.arange(5))[:3]
Posted by: Guest on June-15-2020

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