python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)how to get a random element from an array in python
import random
names=['Mark', 'Sam', 'Henry']
#Set any array
random_array_item=random.choice(names)
#Declare a variable as a random choice
print(random_array_item)
#Print the random choice
#Or, if you want to arrange them in any order:
for j in range(names):
print(random.choice(names))print random string from list python
import random
list = ["Item 1", "Item 2", "Item 3"] # List
item = random.choice(list) # Chooses from list
print(item) # Prints choice
# From stackoverflow
# Tried and tested methodhow to randomly choose from a list python
random.choice(name of list)choose random index from list python
import random # Don't forget to install it first with pip install random
ahahfunny = ['ahah ', 'copy-', 'paste ', 'stack overflow',' go ', 'brrr']
# the biggest index in this list above is 5 (0 being 1 in programming)
print(ahahfunny[random.randint(0, 5)] # I like this way,
print(random.choice(ahahfunny)) # But this way is WAY thiccer...random array in python
import random
Items = ["Item1", "Item2", "Item3", "Item4", "Item5"]
print(random.choice (Items))Copyright © 2021 Codeinu
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