python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)
python choose random element from list
import random
#1.A single element
random.choice(list)
#2.Multiple elements with replacement
random.choices(list, k = 4)
#3.Multiple elements without replacement
random.sample(list, 4)
how to get a random element from an array in python
import random
names=['Mark', 'Sam', 'Henry']
#Set any array
random_array_item=random.choice(names)
#Declare a variable as a random choice
print(random_array_item)
#Print the random choice
#Or, if you want to arrange them in any order:
for j in range(names):
print(random.choice(names))
print random string from list python
import random
list = ["Item 1", "Item 2", "Item 3"] # List
item = random.choice(list) # Chooses from list
print(item) # Prints choice
# From stackoverflow
# Tried and tested method
how to print a random part of a list in python
import random
foo = ['a', 'b', 'c', 'd', 'e']
print(random.choice(foo))
python random choice from list
import random
list = [20, 30, 40, 50 ,60, 70, 80]
sampling = random.choices(list, k=4) # Choices with repetition
sampling = random.sample(list, k=4) # Choices without repetition
how to randomly choose from a list python
random.choice(name of list)
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