check if a list contains an item from another list python
## checking any elment of list_B in list_A
list_A = [1, 2, 3, 4]
list_B = [2, 3, 6]
check = any(item in list_A for item in list_B)
print(check)
# Truecheck if a list contains an item from another list python
## checking any elment of list_B in list_A
list_A = [1, 2, 3, 4]
list_B = [2, 3, 6]
check = any(item in list_A for item in list_B)
print(check)
# Truepython check list contains another list
>>> items = set([-1, 0, 1, 2])
>>> set([1, 2]).issubset(items)
True
>>> set([1, 3]).issubset(items)
Falsecheck if part of list is in another list python
'''
check if list1 contains any elements of list2
'''
result = any(elem in list1 for elem in list2)
if result:
print("Yes, list1 contains any elements of list2")
else :
print("No, list1 contains any elements of list2")how to check if a list contains elements in another list
##Taking examples of two python lists.
##Take examples of two lists.
list1 = [2,4,0,7,6]
list2 = [1,0,9,7,6]
##the statement for condition is.
check = any(element in list2 for element in list1)check if a list contains any item from another list python
## using set
list_A = [1, 2, 3, 4]
list_B = [2, 3]
set_A = set(list_A)
set_B = set(list_B)
print(set_A.intersection(set_B))
# True if there is any element same
# False if there is no element samecheck if a list contains any item from another list python
## using set
list_A = [1, 2, 3, 4]
list_B = [5,1]
set_A = set(list_A)
set_B = set(list_B)
output = False if (set_A.intersection(set_B) == set()) else True
print(output)
# True if there is any element same
# False if there is no element sameCopyright © 2021 Codeinu
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