get all combinations from two lists python
a = ["foo", "melon"]
b = [True, False]
c = list(itertools.product(a, b))
>> [("foo", True), ("foo", False), ("melon", True), ("melon", False)]get all combinations from two lists python
a = ["foo", "melon"]
b = [True, False]
c = list(itertools.product(a, b))
>> [("foo", True), ("foo", False), ("melon", True), ("melon", False)]combination python
# 1. Print all combinations
from itertools import combinations
comb = combinations([1, 1, 3], 2)
print(list(combinations([1, 2, 3], 2)))
# Output: [(1, 2), (1, 3), (2, 3)]
# 2. Counting combinations
from math import comb
print(comb(10,3))
#Output: 120python possible combinations
import math
n=7
k=5
print(math.comb(n, k))python combinations
def permutations(iterable, r=None):
# permutations('ABCD', 2) --> AB AC AD BA BC BD CA CB CD DA DB DC
# permutations(range(3)) --> 012 021 102 120 201 210
pool = tuple(iterable)
n = len(pool)
r = n if r is None else r
if r > n:
return
indices = list(range(n))
cycles = range(n, n-r, -1)
yield tuple(pool[i] for i in indices[:r])
while n:
for i in reversed(range(r)):
cycles[i] -= 1
if cycles[i] == 0:
indices[i:] = indices[i+1:] + indices[i:i+1]
cycles[i] = n - i
else:
j = cycles[i]
indices[i], indices[-j] = indices[-j], indices[i]
yield tuple(pool[i] for i in indices[:r])
break
else:
returnCopyright © 2021 Codeinu
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