Answers for "how to get all possible combinations of an array python"

Python

python all possible combinations of multiple lists

>>> import itertools
>>> a = [[1,2,3],[4,5,6],[7,8,9,10]]
>>> list(itertools.product(*a))
[(1, 4, 7), (1, 4, 8), (1, 4, 9), (1, 4, 10), (1, 5, 7), (1, 5, 8), (1, 5, 9), (1, 5, 10), (1, 6, 7), (1, 6, 8), (1, 6, 9), (1, 6, 10), (2, 4, 7), (2, 4, 8), (2, 4, 9), (2, 4, 10), (2, 5, 7), (2, 5, 8), (2, 5, 9), (2, 5, 10), (2, 6, 7), (2, 6, 8), (2, 6, 9), (2, 6, 10), (3, 4, 7), (3, 4, 8), (3, 4, 9), (3, 4, 10), (3, 5, 7), (3, 5, 8), (3, 5, 9), (3, 5, 10), (3, 6, 7), (3, 6, 8), (3, 6, 9), (3, 6, 10)]

Posted by: Guest on May-18-2020

Source

get all combinations from two lists python

a = ["foo", "melon"]
b = [True, False]
c = list(itertools.product(a, b))
>> [("foo", True), ("foo", False), ("melon", True), ("melon", False)]

Posted by: Guest on April-21-2020

how to find a combination of all elements in a python list

import itertools

stuff = [1, 2, 3]
for L in range(0, len(stuff)+1):
    for subset in itertools.combinations(stuff, L):
        print(subset)

Posted by: Guest on April-05-2021

Source

python get all combinations of list

itertools.combinations(iterable, r)

Posted by: Guest on January-29-2021

how to get all possible combinations in python

all_combinations = [list(zip(each_permutation, list2)) for each_permutation in itertools.permutations(list1, len(list2))]

Posted by: Guest on April-06-2020

Source

combination of 1 2 3 4 5 python

 
a=int(input("Enter first number:"))
b=int(input("Enter second number:"))
c=int(input("Enter third number:"))
d=[]
d.append(a)
d.append(b)
d.append(c)
for i in range(0,3):
    for j in range(0,3):
        for k in range(0,3):
            if(i!=j&j!=k&k!=i):
                print(d[i],d[j],d[k])

Posted by: Guest on December-25-2020

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