reverse key order dict python
>>> a = {0:'000000',1:'11111',3:'333333',4:'444444'}
>>> a.keys()
[0, 1, 3, 4]
>>> sorted(a.keys())
[0, 1, 3, 4]
>>> reversed(sorted(a.keys()))
<listreverseiterator object at 0x02B0DB70>
>>> list(reversed(sorted(a.keys())))
[4, 3, 1, 0]python reverse dict key order
# Python3 using reversed() + items()
test_dict = {'Hello' : 4, 'to' : 2, 'you' : 5}
rev_dict = dict(reversed(list(test_dict.items()))) # Reversing the dictionary
print("The original dictionary : " + str(test_dict))
print("The reversed order dictionary : " + str(rev_dict))
# Output:
"The original dictionary : {'Hello': 4, 'to': 2, 'you': 5}"
"The reversed order dictionary : {'you': 5, 'to': 2, 'Hello': 4}"how to reverse a dictionary in python
def inverse_dict(my_dict):
"""
the func get a dictinary and reverse it, the keys become values and the values become keys.
:param my_dict: the dictinary that need to be reversed.
:return: a VERY pretty dictionary.
"""
result_dict = {}
for key, value in my_dict.items():
if not value in result_dict.keys():
result_dict[value] = []
result_dict[value].append(key)
return result_dict, print(result_dict)reverse python dictionary
inv_map = {v: k for k, v in my_map.iteritems()}Copyright © 2021 Codeinu
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