Answers for "module erro handling in pyth"

print type of exception python

try:
    someFunction()
except Exception as ex:
    template = "An exception of type {0} occurred. Arguments:n{1!r}"
    message = template.format(type(ex).__name__, ex.args)
    print (message)

python exception

try:
  # code block
except ValueError as ve:
  print(ve)