Answers for "decimal python"

python decimal()

Decimal is a python library that allows for more precise decimals, without a 
large amount of floating point errors.
from decimal import *
getcontext().prec = n
The above line let''s you change the precision of the decimal.
i.e.
getcontext().prec = 6
print(Decimal(1) / Decimal(7))
Decimal('0.142857')
You can see that it has 6 digits of prescision.
There are useful functions, 
.log10
.sqrt
.exp
.ln
First, Decimal(x).log10 returns log10(x).
I.e.
print(Decimal(100).log10)
2
Then, Decimal(x).sqrt returns the square root of a number (duh).
Returns the square root of a number
getcontext().prec = 28
Decimal(2).sqrt()
Decimal('1.414213562373095048801688724')
Then .exp is the natural anti-lograthm (natural lograthm is loge(x), where is
e is Euler''s (say Oiler''s) constant, or 2.718...
Since exponentiation is the opposite of lograthms,
Decimal(x).exp = e**x
getcontext().prec = 3
Decimal(1).exp()
Decimal('2.718')
Finally, .ln is the natural lograthm, or loge(x) .
For more info check out 
https://docs.python.org/3/library/decimal.html
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give answer in 6 decimal python

print("{:.6f}".format(variable_name))

fixed precision float python

x = 13.949999999999999999
g = float("{:.2f}".format(x))

decimal in python

>>> from decimal import *
>>> getcontext().prec = 6
>>> Decimal(1) / Decimal(7)
Decimal('0.142857')
>>> getcontext().prec = 28
>>> Decimal(1) / Decimal(7)
Decimal('0.1428571428571428571428571429')

w=how to tell if decimal in python

i = 100
f = 1.23

print(type(i))
print(type(f))
# <class 'int'>
# <class 'float'>

How to solve not in base 10 in python when using decimals

Example = float(input("Question?"))
Example_2 = float(input("Question2?"))
Awnser_1 = float(Example) * float(Example_2)
print = Awnser_1