Answers for "extract text from website python"

1

how to get text from a website python

import requests
from bs4 import BeautifulSoup #pip install bs4

url = 'https://www.troyhunt.com/the-773-million-record-collection-1-data-reach/'
res = requests.get(url)
html_page = res.content
soup = BeautifulSoup(html_page, 'html.parser')
text = soup.find_all(text=True)

output = ''
blacklist = [
    '[document]',
    'noscript',
    'header',
    'html',
    'meta',
    'head', 
    'input',
    'script',
    # there may be more elements you don't want, such as "style", etc.
]

for t in text:
    if t.parent.name not in blacklist:
        output += '{} '.format(t)

print(output)
Posted by: Guest on May-23-2021
0

web scraper python

>>> from bs4 import BeautifulSoup
>>> raw_html = open('contrived.html').read()
>>> html = BeautifulSoup(raw_html, 'html.parser')
>>> for p in html.select('p'):
...     if p['id'] == 'walrus':
...         print(p.text)

'I am the walrus'
Posted by: Guest on August-09-2020
0

web scraper python

def get_hits_on_name(name):
    """
    Accepts a `name` of a mathematician and returns the number
    of hits that mathematician's Wikipedia page received in the 
    last 60 days, as an `int`
    """
    # url_root is a template string that is used to build a URL.
    url_root = 'URL_REMOVED_SEE_NOTICE_AT_START_OF_ARTICLE'
    response = simple_get(url_root.format(name))

    if response is not None:
        html = BeautifulSoup(response, 'html.parser')

        hit_link = [a for a in html.select('a')
                    if a['href'].find('latest-60') > -1]

        if len(hit_link) > 0:
            # Strip commas
            link_text = hit_link[0].text.replace(',', '')
            try:
                # Convert to integer
                return int(link_text)
            except:
                log_error("couldn't parse {} as an `int`".format(link_text))

    log_error('No pageviews found for {}'.format(name))
    return None
Posted by: Guest on August-09-2020

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