numbers to words converter python program
# Number to Words
# Main Logic
ones = ('Zero', 'One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine')
twos = ('Ten', 'Eleven', 'Twelve', 'Thirteen', 'Fourteen', 'Fifteen', 'Sixteen', 'Seventeen', 'Eighteen', 'Nineteen')
tens = ('Twenty', 'Thirty', 'Forty', 'Fifty', 'Sixty', 'Seventy', 'Eighty', 'Ninety', 'Hundred')
suffixes = ('', 'Thousand', 'Million', 'Billion')
def process(number, index):
if number=='0':
return 'Zero'
length = len(number)
if(length > 3):
return False
number = number.zfill(3)
words = ''
hdigit = int(number[0])
tdigit = int(number[1])
odigit = int(number[2])
words += '' if number[0] == '0' else ones[hdigit]
words += ' Hundred ' if not words == '' else ''
if(tdigit > 1):
words += tens[tdigit - 2]
words += ' '
words += ones[odigit]
elif(tdigit == 1):
words += twos[(int(tdigit + odigit) % 10) - 1]
elif(tdigit == 0):
words += ones[odigit]
if(words.endswith('Zero')):
words = words[:-len('Zero')]
else:
words += ' '
if(not len(words) == 0):
words += suffixes[index]
return words;
def getWords(number):
length = len(str(number))
if length>12:
return 'This program supports upto 12 digit numbers.'
count = length // 3 if length % 3 == 0 else length // 3 + 1
copy = count
words = []
for i in range(length - 1, -1, -3):
words.append(process(str(number)[0 if i - 2 < 0 else i - 2 : i + 1], copy - count))
count -= 1;
final_words = ''
for s in reversed(words):
temp = s + ' '
final_words += temp
return final_words
# End Main Logic
# Reading number from user
number = int(input('Enter any number: '))
print('%d in words is: %s' %(number, getWords(number)))