numbers to words converter python program
# Number to Words # Main Logic ones = ('Zero', 'One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine') twos = ('Ten', 'Eleven', 'Twelve', 'Thirteen', 'Fourteen', 'Fifteen', 'Sixteen', 'Seventeen', 'Eighteen', 'Nineteen') tens = ('Twenty', 'Thirty', 'Forty', 'Fifty', 'Sixty', 'Seventy', 'Eighty', 'Ninety', 'Hundred') suffixes = ('', 'Thousand', 'Million', 'Billion') def process(number, index): if number=='0': return 'Zero' length = len(number) if(length > 3): return False number = number.zfill(3) words = '' hdigit = int(number[0]) tdigit = int(number[1]) odigit = int(number[2]) words += '' if number[0] == '0' else ones[hdigit] words += ' Hundred ' if not words == '' else '' if(tdigit > 1): words += tens[tdigit - 2] words += ' ' words += ones[odigit] elif(tdigit == 1): words += twos[(int(tdigit + odigit) % 10) - 1] elif(tdigit == 0): words += ones[odigit] if(words.endswith('Zero')): words = words[:-len('Zero')] else: words += ' ' if(not len(words) == 0): words += suffixes[index] return words; def getWords(number): length = len(str(number)) if length>12: return 'This program supports upto 12 digit numbers.' count = length // 3 if length % 3 == 0 else length // 3 + 1 copy = count words = [] for i in range(length - 1, -1, -3): words.append(process(str(number)[0 if i - 2 < 0 else i - 2 : i + 1], copy - count)) count -= 1; final_words = '' for s in reversed(words): temp = s + ' ' final_words += temp return final_words # End Main Logic # Reading number from user number = int(input('Enter any number: ')) print('%d in words is: %s' %(number, getWords(number)))
