filter function using lambda in python
#filter function
nums1 = [2,3,5,6,76,4,3,2]
bads = list(filter(lambda x: x>4, nums1))
print(bads)filter function using lambda in python
#filter function
nums1 = [2,3,5,6,76,4,3,2]
bads = list(filter(lambda x: x>4, nums1))
print(bads)map function using lambda in python
# Map function
nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)find elements array lamda python
result = [filter(lambda x: (x % 2 == 0), [1, 2, 3])]python array find lambda
lst = [1,2,3,4]
filter(lambda x: x % 2 == 0, lst)
[x for x in lst if x %2 == 0]
#[2,4]map lambda
>>> numbers = [1, 2, 3, 4, 5]
>>> squared = map(lambda num: num ** 2, numbers)
>>> list(squared)
[1, 4, 9, 16, 25]Copyright © 2021 Codeinu
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