filter function using lambda in python
#filter function
nums1 = [2,3,5,6,76,4,3,2]
bads = list(filter(lambda x: x>4, nums1))
print(bads)filter function using lambda in python
#filter function
nums1 = [2,3,5,6,76,4,3,2]
bads = list(filter(lambda x: x>4, nums1))
print(bads)map function using lambda in python
# Map function
nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)find elements array lamda python
result = [filter(lambda x: (x % 2 == 0), [1, 2, 3])]reduce function using lambda in python
#Reduce function
from functools import reduce
list2 =[1,2,3,4,5]
fins = reduce(lambda x,y:x+y, list2)
print(fins)
#o/p : 15
# reduce similar to this concept
list2 =[1,2,3,4,5]
adds = 0
for i in list2:
adds+=i
print(adds)Python Filter List with Lambda
# creating a list in Python
mylist= [3,5,1,5,7,8,2,6]
#filter all the odd numbers using list Comprehension
result = [x for x in mylist if x%2!=0]
print('The odd numbers are ',list(result))
#filter all the even numbers using list Comprehension
result = [x for x in mylist if x%2==0]
print('The even numbers are ',list(result))Copyright © 2021 Codeinu
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