Answers for "lambda x: float(x[1:-1])"

8

map function using lambda in python

# Map function 

nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)
Posted by: Guest on August-07-2020
1

lambda x:x[1]

student_tuples = [
    ('john', 'A', 15),
    ('jane', 'B', 12),
    ('dave', 'B', 10),]
sorted(student_tuples, key=lambda student: student[2])   # sort by age
>>>>[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]
Posted by: Guest on July-25-2020

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