dataframe slice by list of values
In [1]: df = pd.DataFrame({'A': [5,6,3,4], 'B': [1,2,3,5]})
In [2]: df
Out[2]:
A B
0 5 1
1 6 2
2 3 3
3 4 5
In [3]: df[df['A'].isin([3, 6])]
Out[3]:
A B
1 6 2
2 3 3dataframe slice by list of values
In [1]: df = pd.DataFrame({'A': [5,6,3,4], 'B': [1,2,3,5]})
In [2]: df
Out[2]:
A B
0 5 1
1 6 2
2 3 3
3 4 5
In [3]: df[df['A'].isin([3, 6])]
Out[3]:
A B
1 6 2
2 3 3make new dataframe from slice
# You need copy with boolean indexing, new DataFrame constructor is not necessary:
d2 = d1[d1.a > 1].copy()slicing in pandas
# iloc[row slicing, column slicing]
surveys_df.iloc[0:3, 1:4]slicing in pandas
# Select rows 0, 1, 2 (row 3 is not selected)
surveys_df[0:3]pandas df by row index
indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]Copyright © 2021 Codeinu
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