Answers for "list().intersection()"

intersection in list

def intersection(lst1, lst2): 
    lst3 = [value for value in lst1 if value in lst2] 
    return lst3 
  
# Driver Code 
lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69] 
lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26] 
print(intersection(lst1, lst2))

python list INTERSECTION

a = ['apple', 'banana', 'pear']
b = ['fridge', 'stove', 'banana']

a & b == ['banana'] #True