Answers for "opening file path in python"

2

python file from path

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))
Posted by: Guest on November-04-2020
-3

get path of open file python

>>> f = open('/Users/Desktop/febROSTER2012.xls')
>>> f.name
'/Users/Desktop/febROSTER2012.xls'
Posted by: Guest on September-16-2020

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