Answers for "pandas create dataframe from dict with index"

22

pandas dataframe from dict

data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']}
pd.DataFrame.from_dict(data)
Posted by: Guest on March-30-2020
1

create pandas dataframe from dictionary

In [11]: pd.DataFrame(d.items())  # or list(d.items()) in python 3
Out[11]:
             0    1
0   2012-07-02  392
1   2012-07-06  392
2   2012-06-29  391
3   2012-06-28  391
...

In [12]: pd.DataFrame(d.items(), columns=['Date', 'DateValue'])
Out[12]:
          Date  DateValue
0   2012-07-02        392
1   2012-07-06        392
2   2012-06-29        391
Posted by: Guest on May-01-2021
0

dataframe to dict without index

df.to_dict('index')
Posted by: Guest on May-31-2020
0

dataframe to dict without index

df.to_dict('list')
Posted by: Guest on May-31-2020
0

create a dataframe from dict

create a dataframe from dict (function)

import pandas as pd
def create_df():
    data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']}
    return pd.DataFrame.from_dict(data)
create_df()
Posted by: Guest on December-08-2020
0

create a dictionary from index and column pandas

import pandas as pd
df = pd.DataFrame({'Name': ['John', 'Sara','Peter','Cecilia'],
                   'Age': [38, 47,63,28],
                  'City':['Boston', 'Charlotte','London','Memphis']})
df
Posted by: Guest on March-25-2021

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