Answers for "count all duplicates in list as 1 in python"

7

python count repeated elements in a list

# Basic syntax:
dict_of_counts = {item:your_list.count(item) for item in your_list}

# Example usage:
your_list = ["a", "b", "a", "c", "c", "a", "c"]
dict_of_counts = {item:your_list.count(item) for item in your_list}
print(dict_of_counts)
--> {'a': 3, 'b': 1, 'c': 3}
Posted by: Guest on December-15-2020
8

count the duplicates in a list in python

some_list=['a','b','c','b','d','m','n','n']

 my_list=sorted(some_list)
 
duplicates=[]
for i in my_list:
     if my_list.count(i)>1:
         if i not in duplicates:
             duplicates.append(i)
 
print(duplicates)
Posted by: Guest on January-30-2021

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