python count repeated elements in a list
# Basic syntax:
dict_of_counts = {item:your_list.count(item) for item in your_list}
# Example usage:
your_list = ["a", "b", "a", "c", "c", "a", "c"]
dict_of_counts = {item:your_list.count(item) for item in your_list}
print(dict_of_counts)
--> {'a': 3, 'b': 1, 'c': 3}count similar values in list python
MyList = ["a", "b", "a", "c", "c", "a", "c"]
return my_dict = {i:MyList.count(i) for i in MyList}
# returns :
{'a': 3, 'c': 3, 'b': 1}
# OR
from collections import Counter
return my_dict = dict(Counter(MyList))
# returns :
{'a': 3, 'c': 3, 'b': 1}
# the both returns the same so it's up to you to choose the one you prefere ;)how to find the number of times a number appears in python
dict((i, a.count(i)) for i in a)python how to count all elements in a list
List = ["Elephant", "Snake", "Penguin"]
print(len(List))
# With the 'len' function Python counts the amount of elements
# in a list (The length of the list).
# In this case the output is '3' because there are 3 elements in the list.count number items in list python
mylist = ["abc", "def", "ghi", "jkl", "mno", "pqr"]
print(len(mylist))
# output 6Copyright © 2021 Codeinu
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