sort a list by values of another one python
numbers = [1, 2, 3]
letters = ['c', 'a', 'b']
#The numbers array sorted by the letters order
sorted_list = [number for letter, number in sorted(zip(letters, numbers))]
print(sorted_list)
#prints: [2, 3, 1]sort two lists by one python
list1 = [3,2,4,1,1]
list2 = ['three', 'two', 'four', 'one', 'one2']
list1, list2 = zip(*sorted(zip(list1, list2)))how do i sort list in python
my_list = [9, 3, 1, 5, 88, 22, 99]
# sort in decreasing order
my_list = sorted(my_list, reverse=True)
print(my_list)
# sort in increasing order
my_list = sorted(my_list, reverse=False)
print(my_list)
# another way to sort using built-in methods
my_list.sort(reverse=True)
print(my_list)
# sort again using slice indexes
print(my_list[::-1])
# Output
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]
# [99, 88, 22, 9, 5, 3, 1]
# [1, 3, 5, 9, 22, 88, 99]Copyright © 2021 Codeinu
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