sort by index 2d array python
a = [[9, 9, 2], [9, 9, 3], [9, 9, 8], [9, 9, 4], [9, 9, 1], [9, 9, 5]]
b = sorted(a, key=lambda a:a[2])
#b contains the following arrays, sorted by their second index:
[[9, 9, 1], [9, 9, 2], [9, 9, 3], [9, 9, 4], [9, 9, 5], [9, 9, 8]]python order 2d array by secode element
sorted(arr, key=lambda x: x[1])how to bubble sort a 2d array in python
>>> blackjackList = [['harsh', '4', 'chips'], ['ahmed', '25', 'chips'], ['yousef', '1003', 'chips'], ['krushangi', '200', 'chips'], ['bombberman', '1202', 'chips']]
>>> def quicksort(arr):
... if len(arr)==0: return []
... if len(arr)==1: return arr
... left = [i for i in arr[1:] if int(i[1])<int(arr[0][1])] # for descending, exchange
... right = [i for i in arr[1:] if int(i[1])>=int(arr[0][1])] # these two values
... return quicksort(left)+[arr[0]]+quicksort(right)
...
>>> quicksort(blackjackList)
[['harsh', '4', 'chips'], ['ahmed', '25', 'chips'], ['krushangi', '200', 'chips'], ['yousef', '1003', 'chips'], ['bombberman', '1202', 'chips']]Copyright © 2021 Codeinu
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