Answers for "how to represent a number in 8 bit binary python"

1

binary number in python 32 bit

>>> '{:032b}'.format(100)
'00000000000000000000000001100100'
>>> '{:032b}'.format(8589934591)
'111111111111111111111111111111111'
>>> '{:032b}'.format(8589934591 + 1)
'1000000000000000000000000000000000'    # N.B. this is 33 digits long
Posted by: Guest on August-08-2020
4

python int binary

print('{0:b}'.format(3))        # '11'
print('{0:8b}'.format(3))       # '      11'
print('{0:08b}'.format(3))      # '00000011'

def int2bin(integer, digits):
    if integer >= 0:
        return bin(integer)[2:].zfill(digits)
    else:
        return bin(2**digits + integer)[2:]
print(int2bin(3, 6))            # '000011'
Posted by: Guest on May-13-2021

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