python split range equally
def chunks(lst, n):
"""Yield successive n-sized chunks from lst."""
for i in range(0, len(lst), n):
yield lst[i:i + n]
list(chunks(range(10, 75), 10))python split range equally
def chunks(lst, n):
"""Yield successive n-sized chunks from lst."""
for i in range(0, len(lst), n):
yield lst[i:i + n]
list(chunks(range(10, 75), 10))split list into lists of equal length python
[lst[i:i + n] for i in range(0, len(lst), n)]how to break a list unequal size chunks in python
>>> data = [123,452,342,533,222,402,124,125,263,254,44,987,78,655,741,165,597,26,15,799,100,154,122,563]
>>> sizes = [2, 5, 14, 3]
>>> it = iter(data)
>>> [[next(it) for _ in range(size)] for size in sizes]
[[123, 452],
[342, 533, 222, 402, 124],
[125, 263, 254, 44, 987, 78, 655, 741, 165, 597, 26, 15, 799, 100],
[154, 122, 563]]python split range into n groups
import numpy
x = range(25)
l = numpy.array_split(numpy.array(x),6)Copyright © 2021 Codeinu
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