Answers for "python split list into chunks of size n"

2

split array into chunks python

a = [1, 2, 3, 4, 5, 6 ,7 ,8 ,9]

splitedSize = 3
a_splited = [a[x:x+splitedSize] for x in range(0, len(a), splitedSize)]

print(a_splited)
# [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
Posted by: Guest on February-27-2021
8

python split range equally

def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):
        yield lst[i:i + n]
        
list(chunks(range(10, 75), 10))
Posted by: Guest on June-17-2020
8

split list into lists of equal length python

[lst[i:i + n] for i in range(0, len(lst), n)]
Posted by: Guest on March-31-2020
0

split into list into even chunks

def chunks(l, n):
    n = max(1, n)
    return (l[i:i+n] for i in range(0, len(l), n))
Posted by: Guest on May-29-2021
0

how to break a list unequal size chunks in python

>>> data = [123,452,342,533,222,402,124,125,263,254,44,987,78,655,741,165,597,26,15,799,100,154,122,563] 
>>> sizes = [2, 5, 14, 3]
>>> it = iter(data)
>>> [[next(it) for _ in range(size)] for size in sizes]
[[123, 452],
 [342, 533, 222, 402, 124],
 [125, 263, 254, 44, 987, 78, 655, 741, 165, 597, 26, 15, 799, 100],
 [154, 122, 563]]
Posted by: Guest on July-18-2020
-1

split long list into chunks of 100

def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):
        yield lst[i:i + n]
Posted by: Guest on May-12-2021

Code answers related to "python split list into chunks of size n"

Python Answers by Framework

Browse Popular Code Answers by Language