how to get distinct value in a column dataframe in python
df.column.unique()how to get distinct value in a column dataframe in python
df.column.unique()pandas count distinct values in a column
Series.value_counts(self, normalize=False, sort=True, ascending=False, bins=None, dropna=True)unique entries in column pandas
# Import modules
import pandas as pd
# Set ipython's max row display
pd.set_option('display.max_row', 1000)
# Set iPython's max column width to 50
pd.set_option('display.max_columns', 50)
# Create an example dataframe
data = {'name': ['Jason', 'Molly', 'Tina', 'Jake', 'Amy'],
'year': [2012, 2012, 2013, 2014, 2014],
'reports': [4, 24, 31, 2, 3]}
df = pd.DataFrame(data, index = ['Cochice', 'Pima', 'Santa Cruz', 'Maricopa', 'Yuma'])
df
#List unique values in the df['name'] column
df.name.unique()if df[col].unique()==2
df_dict = dict(zip([i for i in df.columns] , [pd.DataFrame(df[i].unique(), columns=[i]) for i in df.columns]))Returns a new DataFrame containing the distinct rows in this DataFrame
# Returns a new DataFrame containing the distinct rows in this DataFrame
df.ditinct().count()
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