python leap year solution
def is_leap(year):
return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)python leap year solution
def is_leap(year):
return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)getting leap year in python
year = int(input("Write any year to check if it is leap year:- "))
if year % 4 == 0:
if year % 100 == 0:
if year % 400 == 0:
print("Leap year.")
else:
print("Not leap year.")
else:
print("Leap year.")
else:
print("Not leap year.")Copyright © 2021 Codeinu
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