Answers for "urllib.parse.urlencode(context))"

python url join

>>> from urllib.parse import urljoin
>>> urljoin('/media/path/', 'js/foo.js')
'/media/path/js/foo.js'

python urlsplit

# The urlsplit() function is an alternative to urlparse(). 
# It behaves a little different, 
# because it does not split the parameters from the URL. 
# This is useful for URLs following RFC 2396, 
# which supports parameters for each segment of the path.
from urlparse import urlsplit
parsed = urlsplit('http://user:pass@NetLoc:80/path;parameters/path2;parameters2?query=argument#fragment')
print parsed
print 'scheme  :', parsed.scheme
print 'netloc  :', parsed.netloc
print 'path    :', parsed.path
print 'query   :', parsed.query
print 'fragment:', parsed.fragment
print 'username:', parsed.username
print 'password:', parsed.password
print 'hostname:', parsed.hostname, '(netloc in lower case)'
print 'port    :', parsed.port