Answers for "parse url python"

python url join

>>> from urllib.parse import urljoin
>>> urljoin('/media/path/', 'js/foo.js')
'/media/path/js/foo.js'

python querystring parse

from urllib.parse import urlparse, parse_qs
URL='https://someurl.com/with/query_string?i=main&mode=front&sid=12ab&enc=+Hello'
parsed_url = urlparse(URL)
parse_qs(parsed_url.query)

how does urllib.parse.urlsplit work in python

>>> urllib.parse.urlparse("http://example.com/pa/th;param1=foo;param2=bar?name=val#frag")
ParseResult(scheme='http', netloc='example.com', path='/pa/th', params='param1=foo;param2=bar', query='name=val', fragment='frag')

urlsplit python

Parse a URL into 5 components:
<scheme>://<netloc>/<path>?<query>#<fragment>
Return a 5-tuple: (scheme, netloc, path, query, fragment).
Note that we don't break the components up in smaller bits
(e.g. netloc is a single string) and we don't expand % escapes.