Answers for "python urlparse"

1

python url join

>>> from urllib.parse import urljoin
>>> urljoin('/media/path/', 'js/foo.js')
'/media/path/js/foo.js'
Posted by: Guest on December-11-2020
0

python querystring parse

from urllib.parse import urlparse, parse_qs
URL='https://someurl.com/with/query_string?i=main&mode=front&sid=12ab&enc=+Hello'
parsed_url = urlparse(URL)
parse_qs(parsed_url.query)
Posted by: Guest on July-18-2020
0

how does urllib.parse.urlsplit work in python

>>> urllib.parse.urlparse("http://example.com/pa/th;param1=foo;param2=bar?name=val#frag")
ParseResult(scheme='http', netloc='example.com', path='/pa/th', params='param1=foo;param2=bar', query='name=val', fragment='frag')
Posted by: Guest on January-11-2021
0

python urlsplit

# The urlsplit() function is an alternative to urlparse(). 
# It behaves a little different, 
# because it does not split the parameters from the URL. 
# This is useful for URLs following RFC 2396, 
# which supports parameters for each segment of the path.
from urlparse import urlsplit
parsed = urlsplit('http://user:pass@NetLoc:80/path;parameters/path2;parameters2?query=argument#fragment')
print parsed
print 'scheme  :', parsed.scheme
print 'netloc  :', parsed.netloc
print 'path    :', parsed.path
print 'query   :', parsed.query
print 'fragment:', parsed.fragment
print 'username:', parsed.username
print 'password:', parsed.password
print 'hostname:', parsed.hostname, '(netloc in lower case)'
print 'port    :', parsed.port
Posted by: Guest on January-11-2021

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