Answers for "url netloc params delimiter"

1

python url join

>>> from urllib.parse import urljoin
>>> urljoin('/media/path/', 'js/foo.js')
'/media/path/js/foo.js'
Posted by: Guest on December-11-2020
0

python querystring parse

from urllib.parse import urlparse, parse_qs
URL='https://someurl.com/with/query_string?i=main&mode=front&sid=12ab&enc=+Hello'
parsed_url = urlparse(URL)
parse_qs(parsed_url.query)
Posted by: Guest on July-18-2020

Python Answers by Framework

Browse Popular Code Answers by Language