python index of max value in list
# any list
a = [1, 7, 3, 12, 5]
# index of minimum element
# if more than 1 minimum,
# first index is returned
min_index = a.index(min(a))
# index of maximum element
max_index = a.index(max(a))python index of max value in list
# any list
a = [1, 7, 3, 12, 5]
# index of minimum element
# if more than 1 minimum,
# first index is returned
min_index = a.index(min(a))
# index of maximum element
max_index = a.index(max(a))python how to return max num index
import numpy as np
x=[1,2,3,4,5]
max_index=np.argmax(x)
# return the index of the maximun element
# max_index has the value 4index of max value of sequence python
a.index(max(a))
a.index(min(a))
mean.max()
max_index = (np.argmax(mean, axis = 0) + 1)find max value in list python
mylist = [1, 7, 3, 12, 5]
min_value = min(mylist)
max_value = max(mylist)max in a list python
li=[0,70,7,89]
max(li)
#gives the max value 89maximum and index of a list pythopn
>>> m = max(a)
>>> [i for i, j in enumerate(a) if j == m]
[9, 12]Copyright © 2021 Codeinu
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