Answers for "Write a program that performs the tasks of a simple calculator. The program should first take an integer as input and then based on that integer perform the task as given below."

python calculator

num_one = int(input("Enter 1st number: "))

op = input("Enter operator: ")

num_two = int(input("Enter 2nd number: "))

if op == "+":
    print(num_one + num_two)
elif op == "-":
    print(num_one - num_two)
elif op == "*" or op == "x":
    print(num_one * num_two)
elif op == "/":
    print(num_one / num_two)

how to make a calculator using idle

def calculate():
    operation = input('''
Please type in the math operation you would like to complete:
+ for addition
- for subtraction
* for multiplication
/ for division
''')

    number_1 = int(input('Please enter the first number: '))
    number_2 = int(input('Please enter the second number: '))

    if operation == '+':
        print('{} + {} = '.format(number_1, number_2))
        print(number_1 + number_2)

    elif operation == '-':
        print('{} - {} = '.format(number_1, number_2))
        print(number_1 - number_2)

    elif operation == '*':
        print('{} * {} = '.format(number_1, number_2))
        print(number_1 * number_2)

    elif operation == '/':
        print('{} / {} = '.format(number_1, number_2))
        print(number_1 / number_2)

    else:
        print('You have not typed a valid operator, please run the program again.')

    # Add again() function to calculate() function
    again()

def again():
    calc_again = input('''
Do you want to calculate again?
Please type Y for YES or N for NO.
''')

    if calc_again.upper() == 'Y':
        calculate()
    elif calc_again.upper() == 'N':
        print('See you later.')
    else:
        again()

calculate()

Calculator in python

num1 = input("Enter a Number : ")
num2 = input("Enter a Number : ")
result = (num1 * num2)
print(result)
# And then print out the result