python get command line arguments
import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))
#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']read argument from terminal
#!/usr/bin/python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
#Terminal
# $ python test.py arg1 arg2 arg3
#print
#Number of arguments: 4 arguments.
#Argument List: ['test.py', 'arg1', 'arg2', 'arg3']how to pass parameters in python script
#!/usr/bin/python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
# python scriptName.py arg1 arg2 arg3
# Output:
# Number of arguments: 4 arguments.
# Argument List: ['test.py', 'arg1', 'arg2', 'arg3']Copyright © 2021 Codeinu
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