Answers for "python take args from command line"

29

python get command line arguments

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']
Posted by: Guest on March-08-2020
9

pass argument to a py file

import sys

def hello(a,b):
    print "hello and that's your sum:", a + b

if __name__ == "__main__":
    a = int(sys.argv[1])
    b = int(sys.argv[2])
    hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"
Posted by: Guest on May-28-2020
11

read argument from terminal

#!/usr/bin/python

import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

#Terminal
# $ python test.py arg1 arg2 arg3

#print
#Number of arguments: 4 arguments.
#Argument List: ['test.py', 'arg1', 'arg2', 'arg3']
Posted by: Guest on May-22-2020
8

python read arguments

#!/usr/bin/python

import sys

print('Number of arguments:', len(sys.argv), 'arguments.')
print('Argument List:', str(sys.argv))
Posted by: Guest on March-01-2020
0

cli args python

import argparse

parser = argparse.ArgumentParser(description='Process some integers.')
parser.add_argument('integers', metavar='N', type=int, nargs='+',
                   help='an integer for the accumulator')
parser.add_argument('--sum', dest='accumulate', action='store_const',
                   const=sum, default=max,
                   help='sum the integers (default: find the max)')

args = parser.parse_args()
print(args.accumulate(args.integers))
Posted by: Guest on October-20-2020

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