Answers for "tkinter filedialog entry"

3

python tkinter filedialog folder

from tkinter import filedialog

								# Where it open to.					# What the window is called.
folder = filedialog.askdirectory(initialdir=os.path.normpath("C://"), title="Example")
Posted by: Guest on January-02-2021
0

tkinter filedialog filename

def open_file():
    file = askopenfile(mode='r', filetypes=[
                       ('Text files', '*.txt'), ('CSV Files', '*.csv')])
    if file is not None:
        print(file.name.split("/")[-1]) # this will print the file name

btn = Button(root, text='Open', command=lambda: open_file())
btn.pack(side=TOP, pady=10)
Posted by: Guest on May-01-2021

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