Answers for "python call list index by reverse ::-1"

55

reverse list python

>>> the_list = [1,2,3]
>>> reversed_list = the_list.reverse()
>>> list(reversed_list)
[3,2,1]

OR

>>> the_list = [1,2,3]
>>> the_list[::-1]
[3,2,1]
Posted by: Guest on February-11-2020
-2

reverse list

records = [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
sorted(records, key=lambda record: record['spam']) # default: ascending
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
sorted(records, key=lambda record: record['spam'], reverse=False) # ascending
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
sorted(records, key=lambda record: record['spam'], reverse=True) # descending
# ==> [{'spam': 2, 'foo': 'a'}, {'spam': 1, 'foo': 'z'}]
# -----------------------
sorted(records, key=lambda dictionary: dictionary['foo']) # default: ascending
# ==> [{'spam': 2, 'foo': 'a'}, {'spam': 1, 'foo': 'z'}]
sorted(records,key=lambda alias: alias['foo'], reverse=True) # descending
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
# -----------------------
print(records)
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}] # NOT modified
Posted by: Guest on June-04-2021

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