Answers for "print reverse list"

5

python reverse list

my_list = [1, 2, 3]
my_list.reverse()           # my_list is modified
print(my_list)              # '[3, 2, 1]'
my_revert = my_list[::-1]   # my_list stays [3, 2, 1]
print(my_revert)            # '[1, 2, 3]'
# Item by item reverse with range(<start>, <end>, <step>)
for i in range(len(my_list), 0, -1):
    print(my_list[i-1])		# '1' '2' '3'
for i in reversed(range(len(my_list))):
    print(my_list[i])       # '1' '2' '3'
Posted by: Guest on May-15-2021
-2

reverse list

records = [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
sorted(records, key=lambda record: record['spam']) # default: ascending
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
sorted(records, key=lambda record: record['spam'], reverse=False) # ascending
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
sorted(records, key=lambda record: record['spam'], reverse=True) # descending
# ==> [{'spam': 2, 'foo': 'a'}, {'spam': 1, 'foo': 'z'}]
# -----------------------
sorted(records, key=lambda dictionary: dictionary['foo']) # default: ascending
# ==> [{'spam': 2, 'foo': 'a'}, {'spam': 1, 'foo': 'z'}]
sorted(records,key=lambda alias: alias['foo'], reverse=True) # descending
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}]
# -----------------------
print(records)
# ==> [{'spam': 1, 'foo': 'z'}, {'spam': 2, 'foo': 'a'}] # NOT modified
Posted by: Guest on June-04-2021

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