reverse list python
>>> the_list = [1,2,3]
>>> reversed_list = the_list.reverse()
>>> list(reversed_list)
[3,2,1]
OR
>>> the_list = [1,2,3]
>>> the_list[::-1]
[3,2,1]reverse list python
>>> the_list = [1,2,3]
>>> reversed_list = the_list.reverse()
>>> list(reversed_list)
[3,2,1]
OR
>>> the_list = [1,2,3]
>>> the_list[::-1]
[3,2,1]reverse for loop python
# 1.
for i in reversed(range(3)): # output: 0
print(i) # 1
# 2
# works with arrays as well , reversed(arr)
# 2.
# another alternative is
arr = [1,2,3]
# note: arr[start : end : step]
for i in arr[::-1]: # output: 0
print(i) # 1
# 2
# 3.
# last alternative i don't recommened!
# note: range(start, end, step)
for i in range(len(arr) - 1, -1 , -1): # output: 0
print(i) # 1
# 2
# read more on range() to understand even better how it works has the same rules as the arraysreverse iteration python
for i in range(10, 0, -1):
#reverses backwards from 10python for loop reverse
my_list = [1, 2, 3]
my_list.reverse() # my_list is modified
print(my_list) # '[3, 2, 1]'
my_revert = my_list[::-1] # my_list stays [3, 2, 1]
print(my_revert) # '[1, 2, 3]'
# Item by item reverse with range(<start>, <end>, <step>)
for i in range(len(my_list), 0, -1): # my_list is [3, 2, 1]
print(my_list[i-1]) # '1' '2' '3'
for i in reversed(range(len(my_list))):
print(my_list[i]) # '1' '2' '3'Copyright © 2021 Codeinu
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