python has duplicates
def has_duplicates(lst):
return len(lst) != len(set(lst))
x = [1,2,3,4,5,5]
has_duplicates(x) # Truepython has duplicates
def has_duplicates(lst):
return len(lst) != len(set(lst))
x = [1,2,3,4,5,5]
has_duplicates(x) # Truehow to make python remove the duplicates in list
mylist = ["a", "b", "a", "c", "c"]
mylist = list(dict.fromkeys(mylist))
print(mylist)duplicate in list python
a = [1,2,3,2,1,5,6,5,5,5]
import collections
print([item for item, count in collections.Counter(a).items() if count > 1])
## [1, 2, 5]program to print duplicates from a list of integers in python
lst = [ 3, 6, 9, 12, 3, 30, 15, 9, 45, 36, 12, 12]
dupItems = []
uniqItems = {}
for x in lst:
if x not in uniqItems:
uniqItems[x] = 1
else:
if uniqItems[x] == 1:
dupItems.append(x)
uniqItems[x] += 1
print(dupItems)find duplicates in list python
def Find_Repeated(x):
x2=sorted(x)
List_Of_Repeated=[]
for i in x2:
if x2.count(i)>1:
List_Of_Repeated.append([i,x2.count(i)])
for c in range(x2.count(i)):
for j in x2:
if i==j and x2.count(i)>1:
x2.remove(i)
List_Of_Repeated.sort()
return List_Of_Repeated
List=[1,2,3,4,4,4,5,5,5,5,5,1,1,2,2,3,7,8,6]
# Repeated numbers: [1,2,3,4,5]
# Simple print output:
print(Find_Repeated(List),"n")
# For a neat output:
print("[ Value , Times Repeated ] n")
print("For example: [2,4] The value 2 was repeated 4 times. n")
for i in Find_Repeated(List):
print(i)Copyright © 2021 Codeinu
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