count the duplicates in a list in python
some_list=['a','b','c','b','d','m','n','n']
my_list=sorted(some_list)
duplicates=[]
for i in my_list:
if my_list.count(i)>1:
if i not in duplicates:
duplicates.append(i)
print(duplicates)python find first duplicate numbers
def findDuplicateNumbers(a):
mySet = set()
for el in a:
if el in mySet:
return el
mySet.add(el)
return -1how to check if there are duplicates in a list python
>>> your_list = ['one', 'two', 'one']
>>> len(your_list) != len(set(your_list))
Truepython remove duplicate numbers
duplicate = [2, 4, 10, 20, 5, 2, 20, 4]
print(list(set(duplicate))python check for duplicate
def checkDuplicate(user):
if len(set(user)) < len(user):
return True
return Falsefind duplicates in list python
def Find_Repeated(x):
x2=sorted(x)
List_Of_Repeated=[]
for i in x2:
if x2.count(i)>1:
List_Of_Repeated.append([i,x2.count(i)])
for c in range(x2.count(i)):
for j in x2:
if i==j and x2.count(i)>1:
x2.remove(i)
List_Of_Repeated.sort()
return List_Of_Repeated
List=[1,2,3,4,4,4,5,5,5,5,5,1,1,2,2,3,7,8,6]
# Repeated numbers: [1,2,3,4,5]
# Simple print output:
print(Find_Repeated(List),"n")
# For a neat output:
print("[ Value , Times Repeated ] n")
print("For example: [2,4] The value 2 was repeated 4 times. n")
for i in Find_Repeated(List):
print(i)Copyright © 2021 Codeinu
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