how to know if a input is a interger in python
whatever = input("Pick an integer > ")
try:
whatever_as_an_integer = int(whatever)
print("That was an integer.")
except ValueError:
print("That is not an integer.")how to know if a input is a interger in python
whatever = input("Pick an integer > ")
try:
whatever_as_an_integer = int(whatever)
print("That was an integer.")
except ValueError:
print("That is not an integer.")python check if input is a number
user_input = input("Enter something:")
if type(user_input) == int:
return user_input
else:
print("Not a number")python check for integer
# From stackoverflow
# If you need to do this, do
isinstance(<var>, int)
# unless you are in Python 2.x in which case you want
isinstance(<var>, (int, long))how to check if a input is an integer python
def check_user_input(input):
try:
# Convert it into integer
val = int(input)
print("Input is an integer number. Number = ", val)
except ValueError:
try:
# Convert it into float
val = float(input)
print("Input is a float number. Number = ", val)
except ValueError:
print("No.. input is not a number. It's a string")python check if input is a number
user_input = input("Enter something:")
if type(user_input) == int:
print("Is a number")
else:
print("Not a number")Copyright © 2021 Codeinu
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