how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) python even or odd
injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
print('This is an odd number')
else:
print('This is an even number')wap in python to check a number is odd or even
num = int(input("Enter a number: "))
if (num % 2) == 0:
print(num ,"is even numbern")
#CODE BY VENOM STONE
else:
print(num,"is Odd numbern")
#CODE BY VENOM STONECopyright © 2021 Codeinu
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