Answers for "how to check if number is odd in for loop python"

10

how to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))  
Posted by: Guest on May-21-2020
-1

fastest way to check odd or even in python

>>> def isodd(num):
        return num & 1 and True or False

>>> isodd(10)
False
>>> isodd(9)
True
Posted by: Guest on September-14-2020

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