odd or even python
# Python program to check if the input number is odd or even.
# A number is even if division by 2 gives a remainder of 0.
# If the remainder is 1, it is an odd number.
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even".format(num))
else:
print("{0} is Odd".format(num))how to find if a value is even or odd in python
num = int(input("Enter a Number:"))
if num % 2 == 0:
print(num , "is even")
else:
print(num , "is odd")how to check if a number is odd python
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even number".format(num))
else:
print("{0} is Odd number".format(num)) how to detect an even number in python
mynumber = int(input("Enter number")) # Ask an integer number to the user
if mynumber % 2 == 0: # % = modelo, It is equal to the rest of the division
print(mynumber, "is an even number")
else: # The rest of 7 / 2 is 2.5, not 0
print(mynumber, "is an odd number")python even or odd
injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
print('This is an odd number')
else:
print('This is an even number')fastest way to check odd or even in python
>>> def isodd(num):
return num & 1 and True or False
>>> isodd(10)
False
>>> isodd(9)
TrueCopyright © 2021 Codeinu
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