Answers for "numpy unique rows"

5

count unique values numpy

number_list = numpy.array([1, 1, 2, 3, 4, 4, 1])
(unique, counts) = numpy.unique(number_list, return_counts=True)
Posted by: Guest on June-20-2021
1

numpy unique axis

#As of NumPy 1.13, one can simply choose the axis for selection of unique values in any N-dim array. To get unique rows, one can do:
import numpy as np
unique_rows = np.unique(original_array, axis=0)
Posted by: Guest on June-17-2021
0

how to find unique values in numpy array

>>> a = np.array(['a', 'b', 'b', 'c', 'a'])
>>> u, indices = np.unique(a, return_index=True)
>>> u
array(['a', 'b', 'c'], dtype='<U1')
>>> indices
array([0, 1, 3])
>>> a[indices]
array(['a', 'b', 'c'], dtype='<U1')
Posted by: Guest on August-03-2021
0

how to find unique values in numpy array

>>> a = np.array([[1, 0, 0], [1, 0, 0], [2, 3, 4]])
>>> np.unique(a, axis=0)
array([[1, 0, 0], [2, 3, 4]])
Posted by: Guest on August-03-2021
0

python .unique()

np.unique([1, 1, 2, 2, 3, 3])
array([1, 2, 3])
Posted by: Guest on August-21-2020

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