Answers for "python time difference in seconds"

Python

python time difference

import datetime
time_1 = datetime.strptime('05:00:00',"%H:%M:%S")
time_2 = datetime.strptime('10:00:00',"%H:%M:%S")

time_interval = time_2 - time_1
print(time_difference)
>>> 5:00:00

OR 
import time
time_1 = time.time()

time.sleep(20)

time_2 = time.time()
time_interval = time_2 - time_1
print(time_interval)
>>> 20.005916118621826

OR 
import datetime
time_1 = datetime.timedelta(hours= 10 , minutes=20, seconds=30)
time_2 = datetime.timedelta(hours= 20, minutes=30, seconds=45)
print(time_2 - time_1)

Posted by: Guest on November-16-2021

python print time difference

>>> import datetime
>>> a = datetime.datetime.now()
>>> b = datetime.datetime.now()
>>> c = b - a

>>> c
datetime.timedelta(0, 4, 316543)
>>> c.days
0
>>> c.seconds
4
>>> c.microseconds
316543

Posted by: Guest on June-11-2020

python difference in dates in seconds

future_date = datetime.datetime(1970, 1, 2)
past_date = datetime.datetime(1970, 1, 1)

difference = (future_date - past_date)
Calculate difference in time


total_seconds = difference.total_seconds()
Convert time difference to seconds


print(total_seconds)
OUTPUT
86400.0

Posted by: Guest on October-11-2020

python difference in time

from datetime import datetime
import time

datetime1 = datetime.datetime.now()
# Wait for 1 minute
time.sleep(60) 
datetime2 = datetime.datetime.now()

difference = datetime2 - datetime1
print(f"The time difference between the 2 time is: {difference}")

Posted by: Guest on September-18-2020

python datetime difference in seconds

import datetime as dt

a = dt.datetime(2013,12,30,23,59,59)
b = dt.datetime(2013,12,31,23,59,59)

(b-a).total_seconds()

Posted by: Guest on June-09-2020

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