Answers for "python open file location"

1

python file location path

import os

print('getcwd:      ', os.getcwd())
print('__file__:    ', __file__)
Posted by: Guest on August-23-2020
1

python open file relative to script location

import os

path = 'a/relative/file/path/to/this/script/file.txt'

with open(os.path.join(os.path.dirname(__file__), path), 'r') as input_file:
    content = input_file.read()
Posted by: Guest on August-31-2020
2

open file in python directory

path = 'C:\Users\Username\Path\To\File'
file=open(path, "r")
Posted by: Guest on May-13-2020
-3

get path of open file python

>>> f = open('/Users/Desktop/febROSTER2012.xls')
>>> f.name
'/Users/Desktop/febROSTER2012.xls'
Posted by: Guest on September-16-2020

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